[Đại 8] Toán chứng minh khó

R

riverflowsinyou1

$a+b+c=\frac{ab+bc+ca}{abc}$ \Rightarrow $a+b+c-ab-bc-ca=0$ \Rightarrow $abc+a+b+c-ab-bc-ca-1=0$ \Rightarrow $(a-1)(b-1)(c-1)=0$
 
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