Câu 3:
x2+x−6+3x−1=3x2−6x+19
⟺x2+x−6+9x−9+6.(x−2)(x+3)(x−1)=3x2−6x+19
⟺3.(x−2)(x+3)(x−1)=x2−8x+17
{a=(x+3)(x−1)b=x−2
→3ab=a2−10b2⟺(a−5b)(a+2b)=0⟺....
Câu 1:
4x2−x+4=3xx+x1
⟺4x2−x+4=3x(x2+1)
{a=x2+1b=x
→4a2−b=3ab⟺...
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