cho sina+sinb=1/2, cosa+cosb=-1/2
tính cos(a+b), tan (a+b)
thank liền
[TEX]sin(a+b)=\frac{1}{2} \Leftrightarrow 2sin(\frac{a+b}{2}).cos(\frac{a-b}{2})=\frac{1}{2} (1)[/TEX]
[TEX]cos(a+b)=\frac{-1}{2} \Leftrightarrow 2cos(\frac{a+b}{2}).cos(\frac{a-b}{2})=\frac{-1}{2} (2)[/TEX]
Lấy (1) chia cho (2) ta được [TEX]tan(\frac{a+b}{2})=-1[/TEX] \Rightarrow [TEX]\frac{a+b}{2}=\frac{-\pi}{4}+k2\pi \Leftrightarrow a+b=\frac{-\pi}{2}+k2\pi[/TEX]