[Đại 10] Giải phương trình

E

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DKXĐ: $x \ge \dfrac{-1}{3}$

PT \Leftrightarrow $2(x-5)(x-1)+5x+15-10\sqrt{3x+1}=0$

\Leftrightarrow $2(x-5)(x-1)+5(x+3-2\sqrt{3x+1})=0$

\Leftrightarrow $2(x-5)(x-1)+5.\dfrac{x^2+6x+9-12x-4}{x+3+2\sqrt{3x+1}}=0$

\Leftrightarrow $2(x-5)(x-1)+5.\dfrac{(x-5)(x-1)}{x+3+2\sqrt{3x+1}}=0$

\Leftrightarrow $x=5$ hoặc $x=1$
 
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