cứu

D

daovuquang

Haiz. Bài siêu dễ:
3/(1^2 . 2^2) + 5/(2^2 . 3^2) + .............................. + 19/(9^2 . 10^2)
=3/1.4+5/4.9+7/9.16+...+19/81.100
=1/1-1/4+1/4-1/9+1/9-1/16+...+1/81-1/100
=1-1/100<1(đpcm)
 
N

ngoctruong95

taco: 3/(1^2.2^2)+5/(2^2.3^2)+....+19/(9^2.10^2)
=(2^2-1^2)/(1^2.2^2)+(3^2-2^2)/(2^2.3^2)+.....+(10^2-9^2)/(9^2.10^2)
=1/1^2-1/2^2+1/2^2-1/3^2+....+1/9^2-1/10^2
=1-1/10^2
mà 1-1/10^2<1=>đpcm (hoc toan phai biet tu duy)
 
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