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E

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$3\sqrt{x-1}+4\sqrt{5-x}=3(\sqrt{x-1}+\sqrt{5-x})+\sqrt{5-x}$ \geq $3\sqrt{x-1+5-x}+0$ \geq 6
Dấu "=" xảy ra \Leftrightarrow $x=5$
 
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