cong thuc nhi thuc newton

N

newstarinsky


Xét khai triển
$(1+x)^{10}=x^0.C^0_{10}+x^1.C^1_{10}+........+x^{10}.C^{10}_{10}$
Thay $x=9$ vào ta được
$(1+9)^{10}=C^0_{10}+9.C^1_{10}+81.C^{2}_{10}+......+9^{10}.C^{10}_{10}$
vậy $s=10^{10}$
 
N

nguyenbahiep1

[TEX]A = C_{10}^0 + 9.C_{10}^1 + 9^2.C_{10}^2 + ... + 9^{10}.C_{10}^10 \\ ( 1+9)^{10} = C_{10}^0.1^10.9^0 + 1^9.9^1.C_{10}^1+....+ 1^0.9^{10}.C_{10}^10 = A \Rightarrow A = (1+9)^{10} = 10^{10} = 10000000000[/TEX]
 
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