co' nha`m hok ? ?

B

bupbexulanxang

sinx-cosx=1

[TEX]sinx-cosx= sinx-sin(\frac{\pi}{2} -x) =2cos.\frac{\pi}{4}.sin(x-\frac{\pi}{4}) =\sqrt{2}.sin(x-\frac{\pi}{4})[/TEX]
===)
PT\Leftrightarrow
[TEX]sin(x-\frac{\pi}{4})=\frac{\sqrt{2}.}{2}[/TEX]
 
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