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hoangcoi9999


Cho a,b,c > 0 CM:
[TEX]\frac{ a^ 2}{b+c} + \frac{ b^ 2}{a+c}+ \frac{ 16c^ 2}{b+a} \geq\frac{ 64c- a-b}{9} [/TEX]
[TEX]\frac{ a^ 2}{b+c} + \frac{ b^ 2}{a+c}+ \frac{ 16c^ 2}{b+a} \geq\frac{ 64c- a-b}{9} [/TEX]
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