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CMR:
Nếu sin(a-b)=[TEX]\frac{1}{3}[/TEX]sin b thì tan(a-b)=[TEX]\frac{sin a}{3+ cos a}[/TEX]
THANKS!
Nếu sin(a-b)=[TEX]\frac{1}{3}[/TEX]sin b thì tan(a-b)=[TEX]\frac{sin a}{3+ cos a}[/TEX]
THANKS!