View attachment 110166
Mn giúp em với ạ ! ><
Ta có:
[tex]coty-cot2y=\frac{sin(2y-y)}{siny.sin2y}=\frac{1}{sin2y}[/tex]
Tương tự [tex]cot2y-cot4y=\frac{1}{sin4y}[/tex]
[tex]cot4y-cot8y=\frac{1}{sin8y}[/tex]
[tex]\Rightarrow coty-cot8y=\frac{1}{sin2y}+\frac{1}{sin4y}+\frac{1}{sin8y}\Rightarrow A=0[/tex]