Áp dụng Viet, ta chỉ cần chứng minh [tex]bc=\frac{1}{2}(k^2-4m_{a}^{2})\frac{1}{1-cosA}[/tex]
[tex]\frac{1}{2}(k^2-4m_{a}^{2})\frac{1}{1-cosA}=\frac{1}{2}(b^2+2bc+c^2-2(b^2+c^2)+a^2)\frac{1}{1-\frac{b^2+c^2-a^2}{2bc}}[/tex]
[tex]=(a^2-b^2-c^2+2bc).\frac{bc}{2bc+a^2-b^2-c^2}=bc[/tex]