[tex]x^4-16x^2+32=0\\\rightarrow (x^2-8-4\sqrt{2})(x^2-8+4\sqrt{2})=0\\\rightarrow x^2=8+4\sqrt{2}\\or\\x^2=8-4\sqrt{2}[/tex]
Có:
[tex]x^2=(\sqrt{6-3\sqrt{2+\sqrt{3}}}-\sqrt{2+\sqrt{2+\sqrt{3}}})^2\\=8-2\sqrt{2+\sqrt{3}}-2\sqrt{6-3\sqrt{2+\sqrt{3}}}.\sqrt{2+\sqrt{2+\sqrt{3}}}\\=8-2\sqrt{2+\sqrt{3}}-2\sqrt{6-3\sqrt{2+\sqrt{3}}}.\frac{\sqrt{6+3.\sqrt{2+\sqrt{3}}}}{\sqrt{3}}\\=8-2\sqrt{2+\sqrt{3}}-2\sqrt{\frac{36-9.(2+\sqrt{3})}{3}}\\=8-2\sqrt{2+\sqrt{3}}-2\sqrt{3(2-\sqrt{3})}\\=8-2(\sqrt{2+\sqrt{3}}+\sqrt{3(2-\sqrt{3})})\\B=\sqrt{2+\sqrt{3}}+\sqrt{3(2-\sqrt{3})}\\\rightarrow B^2=8-2\sqrt{3}+2\sqrt{3.(4-3)}=8-2\sqrt{3}+2\sqrt{3}=8\\\rightarrow B=2\sqrt{2}\\\rightarrow x^2=8-4\sqrt{2}\\\rightarrow dpcm[/tex]