chứng minh

B

bitonruoi1

Last edited by a moderator:
L

lp_qt

Câu 1

$$10+ \sqrt{60}-\sqrt{24}-\sqrt{40}
=10+2\sqrt{15}-2\sqrt{6}-2\sqrt{10}
=2.\sqrt{5}.\sqrt{3}-2\sqrt{2}.\sqrt{3}-2\sqrt{5}.\sqrt{2}+2+3+5
=(\sqrt{5}+\sqrt{3}-\sqrt{2})^2$$

$$\rightarrow \sqrt{10+ \sqrt{60}-\sqrt{24}-\sqrt{40}}=\sqrt{3}+ \sqrt{5}-\sqrt{2} (\sqrt{3}+ \sqrt{5}-\sqrt{2} >0)$$
 
Top Bottom