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Áp dụng
$\dfrac{1}{(\sqrt{a} + \sqrt{a + 1})(a + a +1)}$
$= \dfrac{\sqrt{a + 1} - \sqrt{a}}{a + a + 1}$
$ < \dfrac{\sqrt{a + 1} - \sqrt{a}}{2\sqrt{a}\sqrt{a + 1}} $
$= \dfrac{1}{2}(\dfrac{1}{\sqrt{a}} - \dfrac{1}{\sqrt{a + 1}})$
 
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