chứng minh:

K

khanhtoan_qb

Ta có:
[TEX]a^3 + b^3 + c^3 = a . a^2 + b. b^2 + c. c^2 = a^2(bx + cy) + b^2 (cx + ay) + c^2 (ax + by)= (a^2bx + ab^2y) + (b^2cx + bc^2y) + (ac^2x + a^2cy) = ab (ax + by) + bc (bx + cy) + ac (cx + ay) = abc + bca + cab = 3abc[/TEX] :D
 
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