ta có:
[tex]ab\sqrt{c-1}=ab\sqrt{1(c-1)}\leq ab\frac{1+c-1}{2}=\frac{abc}{2}[/tex]
[tex]bc\sqrt{a-9}=\frac{ab}{3}\sqrt{9(a-9)}\leq \frac{bc}{3}.\frac{9+a-9}{2}=\frac{abc}{6}[/tex]
[tex]ca\sqrt{b-4}=\frac{ca}{2}\sqrt{4(b-4)}\leq \frac{ca}{2}.\frac{4+b-4}{2}=\frac{abc}{4}[/tex]
Công vế với vế ta đc
[tex]VT \leq \frac{abc}{2}+\frac{abc}{6}+\frac{abc}{4}=\frac{11abc}{12}[/tex]