Chứng minh: $\dfrac{1}{a^2+2bc}+\dfrac{1}{b^2+2ac}+\dfrac{1}{c ^2+2ab} \ge 9$

T

thong7enghiaha


2.

Áp đụng BDT Cauchy-Schwarz, ta có:

$\dfrac{1}{a^2+2bc}+\dfrac{1}{b^2+2ac}+\dfrac{1}{c^2+2ab} \ge \dfrac{(1+1+1)^2}{(a+b+c)^2} \ge \dfrac{9}{1}=9$
 
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