4. chứng minh tương đương: [tex]\frac{2cos^2x-1}{cosx+sinx}=cosx-sinx<=>2cos^2x-1=(cosx-sinx)(cosx+sinx)<=>cos2x=cos^2x-sin^2x<=>cos2x=cos2x[/tex]
5. [tex]VT=\frac{1+cosx-sin^2x}{sinx(1+cosx)}=\frac{cos^2x+cosx}{sinx(1+cosx)}=\frac{cosx(1+cosx)}{sinx(1+cosx)}=\frac{cosx}{sinx}=cotx[/tex]