cho căn thức sau:

K

kakashi_hatake

ĐKXĐ x>0, x khác 1
a
Có [TEX]A= \frac{(x+\sqrt{x}+1)(\sqrt{x-2.\sqrt{x} +1})(\sqrt{x^2+4}-2)(\sqrt{x^2+4}+2)}{x(x.\sqrt{x}-1)}=\frac{(x+\sqrt{x}+1)(\sqrt{(\sqrt{x}-1)^2}.(x^2+4-4)}{x(x+\sqrt{x}+1)(\sqrt{x}-1)}=\frac{|\sqrt{x}-1|.x^2}{x(\sqrt{x}-1)}[/TEX]
A=x nếu x > 1
A=-x nếu 0<x<1

b
A=x > 1 >0 \forall x>1
A=-x<0 \forall 0<x<1
 
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