câu hỏi

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nguyenbahiep1

[laTEX]( 1+cos2x)^2 - cos2x - \frac{1}{2}(2cos^22x-1)+ cos(\frac{3x}{4}) = \frac{7}{2} \\ \\ cos2x + cos(\frac{3x}{4}) = 2 \\ \\ \begin{cases} cos2x = 1 \\ cos(\frac{3x}{4}) = 1 \end{cases} [/laTEX]
 
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