Ta có:
(10−3−10+3)2=210−2(10−3)(10+3)=2(10−1)
⇒10−3−10+3=−2(10−1) (vì
10−3<10+3)
$\Rightarrow \dfrac{\sqrt{\sqrt{10}-3}-\sqrt{2}-\sqrt{\sqrt{10}+3}}{\sqrt{2}}+\sqrt{\sqrt{10}-1}
\\=\dfrac{\sqrt{\sqrt{10}-3}-\sqrt{\sqrt{10}+3}}{\sqrt{2}}-1+\sqrt{\sqrt{10}-1}
\\=-\sqrt{\sqrt{10}-1}-1+\sqrt{\sqrt{10}-1}=-1$