T
thanhhoawa


1] [1+ sinx + cosx ]/[1 + sinx]= 2-tanx
2] 3*[cos2x]^2 - 3*[sinx]^2 + [cosx]^2 = 0
3] tan[pi/2] * cosx - sin2x = 0
4] [sinx]^3 * cosx - sinx * [cosx]^3 = 1/2
5] [2sinx - 1]*[2sin2x + 1] = 3 - 4*[cosx]^2
2] 3*[cos2x]^2 - 3*[sinx]^2 + [cosx]^2 = 0
3] tan[pi/2] * cosx - sin2x = 0
4] [sinx]^3 * cosx - sinx * [cosx]^3 = 1/2
5] [2sinx - 1]*[2sin2x + 1] = 3 - 4*[cosx]^2