L
lankuter


tính tích phân. thầy v các b giup e. e thanks
I=[TEX]\int\limit_{1/2}^{2}(x+1-1/x)e^{x+1/x}dx[/TEX]
I=[TEX]\int\limit_{1/2}^{2}(x+1-1/x)e^{x+1/x}dx[/TEX]
kimxakiem2507:
[TEX]I=\int\limit_{1/2}^{2}d(xe^{x+1/x})=xe^{x+1/x}\|_{\frac{1}{2}}^2[/TEX]
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