BT So sánh

N

ngocphuong23

So sánh
$A= \dfrac{10^{10} + 1}{10^{10} - 1}$ và $B= \dfrac{10^{10} - 1}{10^10-3}$
Ta có $\dfrac{10^{10} + 1}{10^{10} - 1} = 1 + \dfrac{2}{10^{10} - 1}$
$ \dfrac{10^{10} - 1}{10^{10} - 3} = 1 + \dfrac{2}{10^{10} - 3}$
Vì $\dfrac{2}{10^{10} - 1}$ < $\dfrac{2}{10^{10} - 3}$ nên $1 + \dfrac{2}{10^{10} - 1}$ < $1 + \dfrac{2}{10^{10} - 3}$ \Rightarrow $A<B$
 
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