bt luong giac

T

thienthanlove20

[TEX]sin^4x + cos^4x = \frac{1}{2}[/TEX]

[TEX]\Leftrightarrow (sin^2x + sin^2x)^2 - 2sin^2xcos^2x = \frac{1}{2}[/TEX]

[TEX]\Leftrightarrow \frac{1}{2}sin^22x = \frac{1}{2}[/TEX]

=> Nghiệm ^^!
 
T

thien_nga_1995

\2. 1+ sinx+cos3x=cosx +sin2x+cos2x
\Leftrightarrow [TEX]1 + sinx + 4cos^3x - 3cosx = cosx + 2sinxcosx +1- 2sin^2x [/TEX]
\Leftrightarrow [TEX]sinx + 4cos^3x - 4cosx - 2sinxcosx + 2sin^2x = 0[/TEX]
\Leftrightarrow[TEX]sinx - 4cosx(1 - cos^2x) - 2sinxcosx + 2sin^2x = 0[/TEX]
\Leftrightarrow [TEX]sinx ( 1 - 4cosxsinx - 2cosx + 2sinx) = 0[/TEX]
 
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