Bdt

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khanh_ndd

Sử dụng bđt Schwarz
[TEX]\frac{4}{a}+\frac{1}{4b}=\frac{1}{a}+\frac{1}{a}+\frac{1}{a}+\frac{1}{a}+\frac{1}{4b}\geq \frac{(1+1+1+1+1)^2}{4(a+b)}=5[/TEX]
 
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