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girlkute_nhockthongay

Cho x+y>6. Tìm min củaP= 3x+2y+6/x+8/y.................................................
[TEX]x+y\ge\ 6[/TEX] chứ nhỉ

ta có [TEX]P=\frac{3}{2}[x+y]+\frac{3}{2}x+\frac{6}{x}+\frac{y}{2}+\frac{8}{y} \ge\ \frac{3}{2}.6+6\sqrt{\frac{x}{2}.\frac{2}{x}}+2\sqrt{\frac{y}{2}\frac{8}{y}}=19[/TEX]
dấu "=" khi x=2; y=4
 
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