bat phuong trinh

H

hoanghondo94

TIM m DE BPT CO NGHIEM [TEX]mx-\sqrt{x-3}\leq m+1[/TEX]
giup minh nhe'.can gap lam

Okie , mình giúp bạn nè :)


[TEX]Dat \ t=\sqrt{x-3} \geq 0\Rightarrow t^2 = x- 3 [/TEX]

[TEX]Bpt \Leftrightarrow f(t) =\frac{1+t}{t^2 +2} \geq m \ co' \ nghiem \ t \geq 0[/TEX]

Lập bbt :

[TEX] Max f(t) \ khi \ t \geq 0 \geq m [/TEX]
 
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