bat phuong trinh va he bpt

N

nguyenbahiep1

[TEX]\sqrt{x^2-2x+3}-\sqrt{x^2-6x+11} > \sqrt{3-x}-\sqrt{x-1} \\ TXD: 1 \leq x \leq 3 \\ \frac{4(x-2)}{\sqrt{x^2-2x+3}+\sqrt{x^2-6x+11}} > \frac{2(2-x)}{\sqrt{3-x}+\sqrt{x-1}} \\ 2.(x-2)(\frac{2}{\sqrt{x^2-2x+3}+\sqrt{x^2-6x+11}}+\frac{1}{\sqrt{3-x}+\sqrt{x-1}}) > 0 \\ \Rightarrow x > 2 \\ \Rightarrow 2 < x \leq 3[/TEX]
 
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