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Cho a>0, b>0, c>0 thỏa mãn: $\dfrac{1}{a} + \dfrac{2}{b} + \dfrac{3}{c} = 3$
Cmr:
$\dfrac{27a^2}{c(c^2+9a^2)} + \dfrac{b^2}{a(4a^2+ b^2)} +\dfrac{8c^2}{b(9b^2+4c^2)} \ge \dfrac{3}{2}$
Cmr:
$\dfrac{27a^2}{c(c^2+9a^2)} + \dfrac{b^2}{a(4a^2+ b^2)} +\dfrac{8c^2}{b(9b^2+4c^2)} \ge \dfrac{3}{2}$
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