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C

chungthuychung

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E

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BĐT \Leftrightarrow $\dfrac{(b+2)+(c+3)}{a+1}+\dfrac{(b+2)+(a+1)}{c+3}+\dfrac{(a+1)+(c+3)}{b+1}=( \dfrac{a+1}{c+3}+\dfrac{c+3}{a+1})+(\dfrac{a+1}{b+2}+\dfrac{b+2}{a+1})+(\dfrac{b+2}{c+3}+\dfrac{c+3}{b+2}) \ge 6$

Dấu "=" xảy ra \Leftrightarrow $a+1=b+2=c+3$ và $a+b+c=6$

\Leftrightarrow $a=3;b=2;c=1$
 
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