bất đẳng thức

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B

braga

$VT=(x+y)(y+z)(z+x)\Bigg(\dfrac{1}{\sqrt{x^2(x+y)(x+z)}}+\dfrac{1}{\sqrt{y^2(y+z)(y+x)}}+ \dfrac{1}{ \sqrt{z^2(z+y)(z+x)}}\Bigg) \\ \geq \dfrac{8}{9}(x+y+z)(xy+yz+zx)\dfrac{3}{\sqrt[3]{(xz+yz)(yx+zx)(zy+xy)}} \\ \geq \dfrac{8}{9}(x+y+z)(xy+yz+zx)\dfrac{9}{2(xy+yz+zx)}=VP$
 
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