Bất Đẳng Thức

A

anhtuanphan

[tex]\frac{1}{a}+\frac{1}{b}+\frac{1}{b}+ \frac{1}{c}+ \frac{1}{c}+\frac{1}{c}>=\frac{6^2}{a+2b+3c}[/tex]
suy ra a+2b+3c>=6
[tex]a+b^2+1+c^3+1+1>=a+2b+3c>=6[/tex]ĐPCM
 
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