bai` vecto kho' na`

C

complete100

Ta có : [TEX]10\sum\vec{A'B}+11\sum\vec{A'C}=30\vec{G'G}+33\vec{G'G}=63\vec{G'G}[/TEX]
Từ giả thuyết: [TEX]\Rightarrow 63\vec{G'G}=\vec{0}[/TEX]

Suy ra: G trùng G' (DONE :) )
 
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