1, [tex]x=\sqrt{7-4\sqrt{3}}=\sqrt{4-4\sqrt{3}+3}=\sqrt{(2-\sqrt{3})^2}=2-\sqrt{3}[/tex]
[tex]\Rightarrow 2-x=\sqrt{3}\Rightarrow \left ( 2-x \right )^2=3\Leftrightarrow x^2-4x+1=0[/tex]
Ta có [TEX]S=x^2-3x-1=x^2-4x+1+x-2=x-2=2-\sqrt{3}-2=-\sqrt{3}[/TEX]