[tex]\int_{0}^{2}\frac{1}{x^2-2x+2}dx=\int_{0}^{2}\frac{1}{(x-1)^2+1}dx[/tex]
Đặt [tex]z=x-1\Rightarrow \int\frac{dx}{(x-1)^2+1}=\int\frac{dz}{z^2+1}[/tex]
Đặt [tex]z=tant\Rightarrow dz=\frac{dt}{cos^2t}\Rightarrow \int\frac{dz}{z^2+1}=\int\frac{\frac{dt}{cos^2t}}{tan^2t+1}=\int dt=t=arctan z=arctan(x-1)[/tex]
[tex]\Rightarrow \int_{0}^{2}\frac{1}{x^2-2x+2}dx=arctan(1)-arctan(-1)=...[/tex]