[TEX]\frac{1}{n\sqrt{n+1}+(n+1)\sqrt{n}}=\frac{n+1-n}{\sqrt{n(n+1)}(\sqrt{n}+\sqrt{n+1})}=\frac{(\sqrt{n}+\sqrt{n+1})(\sqrt{n+1}-\sqrt{n})}{\sqrt{n(n+1)}(\sqrt{n}+\sqrt{n+1})} =\frac{(\sqrt{n+1}-\sqrt{n})}{\sqrt{n(n+1)}}=\frac{1}{\sqrt{n}}-\frac{1}{n+1}[/TEX]
A=[TEX]\frac{1}{1}-\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}+...+\frac{1}{\sqrt{99}}-\frac{1}{\sqrt{100}}=1-\frac{1}{10}=\frac{9}{10}[/TEX]
2/ đặt [TEX] ({\frac{x-1}{x-2}})^{2}[/TEX] = a [TEX] ({\frac{x+1}{x+2}})^{2}[/TEX] =b
có [TEX]{a}^{2}+{b}^{2}-\frac{5}{2}ab=0\Leftrightarrow 2{a}^{2}+2{b}^{2}-5ab=0\Leftrightarrow (2a-b)(2b-a)=0[/TEX]