2, 4vt EA +2 vt EB +3vt EC =0
nên 4 vt EA +2 vt EA +2vt AB +3vt EA +3 vt AC =0
hay 9 vt AE= 2 vt AB +3 vt AC
nên vt AE = 2/9 vt AB + 1/3 vt AC (1)
còn vt AD= vt AB +vt BD =vt AB +3/5 vt BC
= vt AB +3/5 (vt BA +vt AC )
= 2/5 vt AB +3/5 vt AC (2)
tuw (1) vaf (2) 2/9 : 2/5 =1/3 :3/5 hay vt AE =5/9 vt AD nên A,E ,D thẳng hàng