A
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cos2x-cos6x+4(3sinx-4sin(^3)3x+1)=0
(cos2x-cos6x+4(3sinx - 4sin mũ3 3x +1))
giai dc xin pm scorpius_nmt@yahoo.com
gui cho minh nhe!!
cos(^2)x+cos(^2)8x=1/2cos10x
(cos bình phương 2x+cos bình phương 8x=1/2 cos10x)
(cos2x-cos6x+4(3sinx - 4sin mũ3 3x +1))
giai dc xin pm scorpius_nmt@yahoo.com
gui cho minh nhe!!
cos(^2)x+cos(^2)8x=1/2cos10x
(cos bình phương 2x+cos bình phương 8x=1/2 cos10x)
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