N
nhat2701


Bài 1/ a) x-291/1704 + x-293/1702 + x-295/1700 = 3
b) x+2/327 + x+3/326 + x+4/325 + x+350/7 = 0
c/ x+25/75 + x+30/70 = 3+35/65 + x+40/60
d/ 99-x/101 + 97-x/103 + 95-x/105 + 93-x/107 = -4
e/ x+14/86 + x+15/85 + x+16/84 + x+17/83 + x+116/4 = 0
f/ x-49/50 + x-50/49 = 49/x-50 + 50/x-49
*P/s: Vd: x-291/1704 có nghĩa là x-291 phần 1704
b) x+2/327 + x+3/326 + x+4/325 + x+350/7 = 0
c/ x+25/75 + x+30/70 = 3+35/65 + x+40/60
d/ 99-x/101 + 97-x/103 + 95-x/105 + 93-x/107 = -4
e/ x+14/86 + x+15/85 + x+16/84 + x+17/83 + x+116/4 = 0
f/ x-49/50 + x-50/49 = 49/x-50 + 50/x-49
*P/s: Vd: x-291/1704 có nghĩa là x-291 phần 1704