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ducnghia97
![](https://blog.hocmai.vn/wp-content/uploads/2017/07/hot.gif)
![](https://blog.hocmai.vn/wp-content/uploads/2017/07/hot.gif)
Giải các phương trình sau:
a/ [tex]\sqrt{x^2+12} +5 = 3x + [tex]\sqrt{x^2+5} b/ x^2 -1 = 2x[tex]\sqrt{x^2- 2x} c/ (x-2)(x+2) +4(x-2)[tex]\sqrt{x+2/x-2} = -3 d/ [tex]\sqrt{x^2- 3x+2} +[tex]\sqrt{x+3} = [tex]\sqrt{x-2} +[tex]\sqrt{x^2 +2x-3} e/ [tex]\sqrt{x+6} +[tex]\sqrt{x-3} - [tex]\sqrt{x-1} - [tex]\sqrt{x-2} =0 f/ 5[tex]\sqrt{2x^3= 16}= 2x^2 +16 g/ 4[tex]\sqrt{x^3-1}= x^2 +4x-2 h/ [tex]\sqrt{x^2 +2x} + [tex]\sqrt{2x-1} = [tex]\sqrt{3x^2 +4x+1}[/tex]
a/ [tex]\sqrt{x^2+12} +5 = 3x + [tex]\sqrt{x^2+5} b/ x^2 -1 = 2x[tex]\sqrt{x^2- 2x} c/ (x-2)(x+2) +4(x-2)[tex]\sqrt{x+2/x-2} = -3 d/ [tex]\sqrt{x^2- 3x+2} +[tex]\sqrt{x+3} = [tex]\sqrt{x-2} +[tex]\sqrt{x^2 +2x-3} e/ [tex]\sqrt{x+6} +[tex]\sqrt{x-3} - [tex]\sqrt{x-1} - [tex]\sqrt{x-2} =0 f/ 5[tex]\sqrt{2x^3= 16}= 2x^2 +16 g/ 4[tex]\sqrt{x^3-1}= x^2 +4x-2 h/ [tex]\sqrt{x^2 +2x} + [tex]\sqrt{2x-1} = [tex]\sqrt{3x^2 +4x+1}[/tex]