ai làm đc làm hộ mình nhé

N

nguyenbahiep1

4sin x^3.cos 3x + 4cos^3.sin 3x + 3√3cos 4x =3

[laTEX](3sinx-sin3x).cos3x + (3cosx + cos3x)sin3x + 3.\sqrt{3}.cos4x - 3 = 0 \\ \\ 3sin4x + 3.\sqrt{3}.cos4x - 3 = 0 \\ \\ sin4x+\sqrt{3}.cos4x = 1 \\ \\ sin(4x+\frac{\pi}{3}) = \frac{1}{2}[/laTEX]
 
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