N
nguyenquanghu1
![](https://blog.hocmai.vn/wp-content/uploads/2017/07/hot.gif)
![](https://blog.hocmai.vn/wp-content/uploads/2017/07/hot.gif)
Mong giải hộ mình cái
Căn2nhâncos13x=sinx+cosx
Căn2nhâncos3x=sinx+cosx
sin2x+4tanx=9căn3chia2
3/sin^2x+tan^2x+tanx+cotx=1
Căn2nhâncos13x=sinx+cosx
Căn2nhâncos3x=sinx+cosx
sin2x+4tanx=9căn3chia2
3/sin^2x+tan^2x+tanx+cotx=1