b)[tex]k(x)=2x+\frac{1}{x^2}=x+x+\frac{1}{x^2}\geq 3\sqrt[3]{x.x.\frac{1}{x^2}}=3[/tex]
Dấu "=" xảy ra tại x = 1.
c)[tex]k(x)=x+\frac{3}{x}=\frac{3}{x}+\frac{3}{4}x+\frac{1}{4}x\geq 2\sqrt{\frac{3}{4}x.\frac{3}{x}}+\frac{1}{4}.2=2.\frac{3}{2}+\frac{1}{2}=\frac{7}{2}[/tex]
Dấu "=" xảy ra tại x = 2.
d)[tex]k(x)=2x+\frac{1}{x^2}=x+x+\frac{1}{8x^2}+\frac{7}{8x^2}\geq 3\sqrt[3]{x.x.\frac{1}{8x^2}}+\frac{7}{8.(\frac{1}{2})^2}=3.\frac{1}{2}+\frac{7}{2}=5[/tex]
Dấu "=" xảy ra tại x = [tex]\frac{1}{2}[/tex]