[TEX]\frac{9}{10!}+ \frac{9}{11!}+ \frac{9}{12!}+...+\frac{9}{1000!} = \frac{10-1}{10!}+ \frac{11-2}{9!}+ \frac{12-3}{12!}+...+ \frac{1000-991}{1000!} = \frac{1}{9!}- \frac{1}{11!}- \frac{2}{12!}- \frac{3}{13!}-...- \frac{989}{999!}- \frac{991}{1000!} < \frac{1}{9!}[/TEX]