[12] toán về đạo hàm

V

vuhoang_97

C

consoinho_96

ta có
[tex] f(x_o)=x_0^3+3x_0^2+4x_0+1[/tex]
[tex] f(x_0+\triangle \ x)= (x_0 +\triangle \ x)+ 3(x_0+\triangle \ x)^2+4(x_0+\triangle \x)+1 [/tex]
[tex] \triangle \y=f(x_0+\triangle \ x)-f(x_0)[/tex]
[tex]\lim_{\triangle x\to 0} f(x)=\frac{\triangle \ y}{\triangle \ x}[/tex]
.............
\Rightarrow [tex] y'=3x^2+6x+4[/tex]
 
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