1 cau kho

G

girlbuon10594

[TEX]AgNO_3 \to Ag + \frac{1}{2} O_2 + NO_2 [/TEX]

\Rightarrow [TEX]n_{NO_2}=0,1[/TEX]

[TEX]Cu + \frac{1}{2} O2 \to CuO [/TEX]

[TEX]O_2[/TEX] hết \Rightarrow Khí X là [TEX]NO_2[/TEX]

[TEX]3NO_2 + H_2O \to 2 HNO_3 + NO[/TEX]
0,1..........................[TEX]\frac{1}{15}[/TEX]

[TEX]n_{HNO_3}=\frac{1}{15}[/TEX]

\Rightarrow [TEX][H^+]=\frac{1}{15}[/TEX] \Rightarrow [TEX]pH=1,18[/TEX]
 
You must log in or register to reply here.
Top Bottom