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jamesborn


chứng minh rằng
[tex](1+\frac{1}{cosx})(1+\frac{1}{cos2x})(1+\frac{1}{cos4x})(1+\frac{1}{cos8x})=(\frac{tan8x}{tan\frac{x}{2}})[/tex]
[tex](1+\frac{1}{cosx})(1+\frac{1}{cos2x})(1+\frac{1}{cos4x})(1+\frac{1}{cos8x})=(\frac{tan8x}{tan\frac{x}{2}})[/tex]