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  1. Kitirts

    Toán toán 8 chương 1

    B1 : (x+2)(x+3)(x+4)(x+5)-8 =(x^2+7x+10 )(x^2+7x+12)-8 =(x^2+7x+10)^2+2(x^2+7x+10)-8 =[(x^2+7x+10)^2+2(x^2+7x+10)+1]-9 =(x^2+7x+11)^2-9 =(x^2+7x+7)(x^2+7x+13)
  2. Kitirts

    Chào

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